person apeepeepoopoo
insert_invitation 13-02-2023

Zwroty na naklejkach:
APU
2,₁ = (x² + In (5x-3y²)) ¹ (2+($x-3y²)) = ( x² +1 (5x-1)) + (2x + 5 A x+ Sa 5 2|5x- Glas B B a 22 A 5 5x-3y (4) 9/2 9/2 U.U. 18) (8) *Uls) Thpt = Ing(4.0). Jbg2=Ibg (0, A). Ibg4=(-4.0); 2(/bg4-lbgl) 1+2+/bg/bg4-4/0 2(bg3-g2) +ng+ng+g4-4/bg0
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